Question

A concave mirror of radius of curvature 20 cm produces an inverter images 3 times the size of an object placed on and perpendicular to the axis.calculate the position of the object and image

Answer 1

Explanation:

Given,

Focal length, f=−30 cm if u=−x

real ⇒ same side ⇒v=−ve

Magnification, m=

u

v

⇒v=m×u=3×(−x)=−3x

From mirror formula,

f

1

=

v

1

+

u

1

We get

−30

1

=

−3x

1

+

−x

1

⇒

30

1

=

3x

1+3

⇒

4

3x

=3⇒x=40 cm

So object should be placed at 40 cm to the mirror.

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