A concave mirror of radius of curvature 40 cm can be rotated about an axis
perpendicular to the plane of the paper passing through point A as shown. A ray of light
parallel to the principal axis is passing through the pole after reflection. The mirror is
rotated about the axis (Passing through A and perpendicular to plane of diagram) by an
angle of 5x so that the ray of light now passes through C (the centre of curvature
before rotation). Find x in degrees
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Answer:
Light incident from particle P will be reflected at mirror
u=−5cm,f=−
2
R
=−20cm
v
1
+
u
1
=
f
1
v
1
=+
3
20
cm
This image will act as object for light getting refracted at water surface
So, object distance d=5+
3
20
=
3
35
cm
below water surface,
After refraction, final image is at
d
′
=d(
μ
1
μ
2
)
=(
3
35
)(
4/3
1
)
=
4
35
=8.75cm
≈8.8cm
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