A concave mirror of radius of curvature 40 cm , produces an image that is 5 times the size of the object. What is the distance between object and its image? [ Answer only if you know the solution!!!]
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Answer:
The answer is 96 cm
Explanation:
Given,
R=40cm So,f=20 cm
M=(-v/u)=5 [v is -ve bcoz the image is virtual as its magnified]
So, v=(-5u)
Using Mirror Formula
(1/f)=(1/u)+(1/v)
(1/20)=(1/u)-(1/5u)
u=16 cm v=-5×16=-80
Now we know virtual image in concave mirror are formed on the opposite side of mirror
So, Distance between object and image = u+v
=16+80 (taking magnitude only)
=96 cm
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