A concave mirror producer a real image 1cm tall of an object 2.5mm tall placed 5cm from the mirror.Find the position of the image and the focal length of the mirror
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hi = -1 cm
ho= 2.5mm = 0.25 cm
U= -5 cm
now hi/ho=- v/U
-1/0.25= -v/-5
so
-4/1 = -v/-5.
ho= 2.5mm = 0.25 cm
U= -5 cm
now hi/ho=- v/U
-1/0.25= -v/-5
so
-4/1 = -v/-5.
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