A concave mirror producers a real image of size 3 time that of the object at a distance of 30 from the pole of the mirror. find the position of the object.
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Object distance=u=30cm (by sign convention)
v=?
Height of object be=h cm
Height of image=3h cm (real image)h=-v/u
m=height of image/height of object
=>3h/h=v/u
=>h3=v/u
=>v=uX3
=>u=•30cm
we get v =30×3
=>90cm
=>>Negative signs indicates that image formed is real and inverted at distance of 90cm from mirror.
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