Question

A concave mirror produces a magnification of +5.find the natute and position of the image and also the position of the object

Answer 1

Answer:

As the magnification is +5.....

Therefore the nature of the image is magnified or enlarged by a factor of 5 and also erect and virtual...

The image is located behind the mirror.....

The position of the object is between the pole and the principal focus...

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Answer 2

Given:

Magnification $=+5$

To find:

1. Nature of the image
2. Position of the image
3. Position of the object.

Solution:

We have been given that the concave mirror gives a magnification of $+5$.

Step 1

We know, magnification by a mirror is given by

$m=\frac{h'}{h}$

where, $h'$ is the height of the image and $h$ is the height of the object.

Hence, we get

$+5=\frac{h'}{h}$

$h'=5$ × $h$

Therefore, we understand that the image of the object is enlarged (5 times the height of object) and erect since we have the positive sign.

Step 2

We also know that, a concave mirror produces an enlarged and erect image only when the object is placed between the focus and the pole of the mirror.

Step 3

In a concave mirror, for an object placed between the pole and focus of the concave mirror, the image of the object is produced behind the concave mirror.

Therefore, the image produced of the object is necessarily virtual.

Final answer:

For a magnification of +5, the object is placed between pole and focus of the concave mirror.

The image produced of the object is virtual ,erect ,enlarged and is produced behind the mirror.