A concave mirror produces a real image 10mm tall, of an object 2.5 mm tall placed at 5 cm from the mirror. Calculate the focal length and position of the image.
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Answered by
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Given- hi= -10mm ho=2.5mm u= -50mm or -5cm
To find- v & f
Solution- hi/ho = - v/u
or, - v = -100/25 * -50
or, v = -200mm or -20 cm
By mirror formula,
1/v + 1/u = 1/f
1/f = 1/-20 + 1/-5
F = -0.25 cm
To find- v & f
Solution- hi/ho = - v/u
or, - v = -100/25 * -50
or, v = -200mm or -20 cm
By mirror formula,
1/v + 1/u = 1/f
1/f = 1/-20 + 1/-5
F = -0.25 cm
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Answered by
1
Answer:
Explanation:
Given- hi= -10mm ho=2.5mm u= -50mm or -5cm
To find- v & f
Solution- hi/ho = - v/u
or, - v = -100/25 * -50
or, v = -200mm or -20 cm
By mirror formula,
1/v + 1/u = 1/f
1/f = 1/-20 + 1/-5
F = -0.25 cm
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