Question

A concave mirror produces a real image of half the size of an object placed at 60 cm infront of it. Where should the object be placed to obtain a virtual image of double the size of the object.

Answer 1

Explanation:

ANSWER

intial object distance u = -60cm(real object_)

magnification m =−

2

1

from m=

u−f

−f

from above f=−20cm

let the object distance be u

′

magnification m

′

=2× image of virtual real object

m=

u

′

−f

−f

2=

u

′

+20

20

⟹u

′

=10cm

hence the object should be at a distance of 10cm infront of the mirror