.A concave mirror produces an image of 2 cm tall, when an object of 5 mm tall is placed at a distance of 10 cm from the mirror. Calculate the image distance and Focal length of the mirror
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Answer:
h = 0.5 cm
h’ = -2 cm
u = -10 cm
m = h’/h = -v/u
-2/0.5 = -v/-10
V = -40 cm
1/v + 1/u = 1/f
1/(-40) + 1/(=10) = 1/f
1/f = (-1 -4)/40
1/f = -5/40
F = -40/5
F = -8 cm
Hence the focal point will be -8 cm and the height real image of the object will be 40 cm.
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