Question

a concave mirror produces three time magnified (enlarged) real image of an object placed at 10cm in front of it. where is the image located ​

Answer 1

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⭕Let the height of the image be 3h amd object, h

so, we know that

3h/h = -(10/u)

Solving we get u as (-10/3)

Answer 2

A concave mirror produces three times magnified real image of an object placed 10cm in front of it.

As we know that;

• m = $\dfrac{-v}{u}$ = $\dfrac{h'}{h}$ ...(1)

Here;

m = magnification

v = distance of image from mirror

u = distance of object from mirror

h = height of image

h' = height of object

A.T.Q.

u = -10 cm

h' = 3h

We have to find where is image located.

Means distance of the image from mirror (v).

Put value of u and h in eq. (1)

m = $\dfrac{-v}{-10}$ = $\dfrac{3h}{h}$

$\dfrac{+v}{10}$ = 3

v = 3 × 10

$\bold{v\: =\: 30\: cm}$

So, the image is locate 30cm away from mirror.

* $\boxed{More\: Information}$

In concave mirror :

• u (distance of object from mirror) = -ve

• v (distance of image from mirror) = -ve but +ve when object is between Focus and pole.

• F (focal length) = -ve

• h (height of object) = +ve

• h' (height of image) = -ve but +ve when object is between Focus and pole.

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