Question

a concave mirror produces three times enlarged virtual image of an object placed at 10 cm in front of it calculate the radius of curvature of the mirror​

Answer 1

Answer:

15cm

Explanation:

Given,

The image formed is in front of a concave mirror which is real. Therefore, magnification is negative.

m = -3

u = -10cm

m = frac−vu

v = -30

From mirror formula, we know

frac1v+frac1u=frac1f frac1v+frac1−10=frac1f

Solving the above equation, we get f = -7.5cm

Therefore, radius of curvature, R = 2f = 15cm.

Answer 2

Hey! Here is your solution:

Given:

Virtual and enlarged image

Object distance= -10

m=(+3)

To find:

Radius of curvature

Solution:

Using magnification formula

$m = \frac{ - v}{u}$

$- 3 = \frac{ - v}{ - 10}$

$v = - 30$

Using mirror formula

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

$\frac{1}{f} = \frac{ - 1}{30} - \frac{1}{10}$

$\frac{1}{f} = \frac{ - 2}{15}$

$f = - 7.5cm$

R=2F

R=(-15cm)

Hope it helps!