Question

A concave mirror produces three times magnified (enlarged) real image
of an object placed at 10 cm in front of it. Where is the image located?​

Answer 1

Answer:

here ,linear magnification ,m= -3(negative sign for real image is inverted).

object diatance,u= -10cm,image distance,v=?

as,m= -v/u

= -3 = -v/-10

= -v =-3*-10

= -v = 30

= v= -30cm

Answer 2

Hey Soul ❤

Your Answer :

Magnification produced by a spherical mirror :

m = Height of the image/Height of the object

= Image Distance/Object Distance

m = h'' / h' = - ( v / u )

Let the height of the object, h' = h

Then, height of the image, h'' = -3h

( here image distance is in minus so it should be real )

now,

-3h/h = - v/u

v/u = 3

Object distance (u)= - 10 cm { Given }

v = 3 × ( - 10 ) = - 30 cm

Therefore, the negative sign indicates that an inverted image is formed in front of the given concave mirror at a distance of 30 cm.

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