CBSE BOARD X, asked by ss994614, 1 month ago

A concave mirror produces three times magnified (enlarged) real image of an object placed at 10 cm in front of it. Where is the image located? ​

Answers

Answered by priyanshukumar6475
1

Explanation:

given,

m=3cm

u=-10cm

v=?

as,

m=-v/u

3=-v/-10

10*3=v

30=v

v=30cm

Answered by DeeznutzUwU
0

       \text{\huge \underline{Answer:}}

       \text{Given parameters are:}

       \text{Object's distance from the mirror}(u) = -10 \text{ cm}

       \text{Image's distance from the mirror} = v

       \text{Height of object} = h

\implies \text{Height of image}(h') = 3h

       \text{We know that magnification of a mirror}(m) = \dfrac{-v}{u} = \dfrac{h'}{h}

\implies \dfrac{-v}{u} = \dfrac{h'}{h}

\implies \dfrac{-v}{-10} = \dfrac{3h}{h}

\implies \dfrac{v}{10} = \dfrac{3}{1}

\implies v = 30 \text{ cm}

 \therefore \text{ }\text{ }\boxed{\boxed{\text{The image is located 30 cm behind the concave mirror}}}

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