Physics, asked by mrijvan, 10 months ago

a concave mirror produces three times magnified real image of the object placed at 10 cm in front of it where is the image is located calculate the radius of curvature

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Answered by Anonymous
9

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Answered by shivanisoni98
12
Given,
Mirror (concave)
Magnification (3times)
object distance (u) =10cm
Image distance (v) =?and radius of curvature (R) =?
By magnification formula, M=-V/U
so, 3=v/10,V(image distance) =10*3=30cm
therefore the image distance of concave mirror is 30cm.
According to mirror formula -1/v+1/u=1/f
Now, we know the v(image distance) and u(object distance).
1/30+1/-10=1/f(object distance of a concave mirror is negative)
1/30-1/10=1-3/30=-2/30
therefore,focal length of concave mirror is -15cm.
so, 2f=R
hence, radius of curvature will be 30cm.
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