a concave mirror with a focal length of 10m creates a real image 30cm away on its principal axis the corresponding object is located how far from the mirror?
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Answer:
What the problem gives us is: f = 10.0 cm, and
d
i
= +30.0 cm. We know that
d
i
is positive because it forms a real image. So we are solving for
d
o
. Isolating the unknown to its own side of the equation, in this case by subtracting
1
d
i
from both sides, will accomplish this.
1
d
o
=
1
f
−
1
d
i
1
d
o
=
1
10
−
1
30
. FInd a common denominator.
1
d
o
=
3
30
−
1
30
1
d
o
=
2
30
. To find
d
o
, take the reciprocal.
d
o
=
30
2
=
+
15.0
c
m
The same process can be used if you know the distance from the object to the vertex of the mirror, and are looking for
d
i
.
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