Physics, asked by tuduraghunath8, 8 months ago

A concave shaving mirror is construction so that a man at a distance of 20 cm from the mirror sees his image magnified 1.5 times . what is the radius of curvature of the mirror ? ​

Answers

Answered by Cosmique
24

Given :

→ position of object (person) , u = -20 cm

→ Magnification produced by concave mirror , m = 1.5

( positive magnification because image is seen by the person and hence , the image will be virtual and erect )

To find :

→  Radius of curvature of mirror , R = ?

Formulae required :

Formula for magnification of mirror

  • m = - v / u

Mirror formula

  • 1/f = 1/v + 1/u

Radius of curvature is twice the focal length of mirror

  • R = 2 f

( where m is magnification , f is focal length , R is radius of curvature , v is position of image and u is position of object )

Solution :

Let , position of image = v

focal length of mirror = f

Using formula for magnification

→  m = - v / u

→  1.5 = - v / -20

→  - v = 1.5 × (-20)

→ - v = -30

→  v = 30 cm

Using Mirror formula

→  1/f = 1/v + 1/u

→  1/f = 1/(30) + 1/(-20)

→  1/f = (2-3) / 60

→  1/f = -1 / 60

→  f = -60 cm

Using formula  R = 2 f

→  R = 2 f

→  R = 2 (-60)

→  R = -120 cm

therefore,

Radius of curvature of mirror is 120 cm . ( where negative sign in R = -120 cm shows that Center of curvature is on negative principal axis. )

Answered by pshubhangi8877
0

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