Physics, asked by srshjkml4298, 1 year ago

a concave spherical mirror forms a 40 cm high realm image of an object whose height is 10 cm the radius of the mirror is 60 cm find the distance from the object to its image

Answers

Answered by MdUmair
9
hey bro here is ur answer...........
M=V/U=I/O=40/10=4
then
U=V/4
then
1/F=1/V-1/U
but F=R/2
then F=30cm
1/30=1/V+1/V/4
THEN
V=150cm
the U=V/4
THEN
U=27.5
THEN
U+V=177.5




HOPE HLP
Attachments:
Answered by irshadsyed281
46

{\bold{{\underline{\red{G}\pink{iv}\green{en}\purple{:-}}}}}

  • Height of image (h') = 40 cm
  • Height of object (h) = 10 cm
  • Radius of mirror (r) - 60 cm
  • Focal length (f) = \bold{\frac{r}{2}}
  • Focal length (f) = \frac{-60}{2}
  • Focal length (f) = - 30 cm

{\bold{{\underline{\red{Formulas}\pink{\:to\:be}\green{\:used}\purple{:-}}}}}

  • Magnification (m) = \bold{\frac{Image\:height\:(h')}{Object\:height\:(h)}}                    

(or)

  • Magnification (m) = \bold{\frac{-\: Image\:distance\:(-v)}{Object\:distance\:(u)}}

  • \bold{\frac{1}{Image\:distance\:(\frac{1}{v} )}\: +\: \frac{1}{Object\:distance\:(\frac{1}{u} )} \:=\:\frac{1}{Focal\:length\:(\frac{1}{f} )} }

{\bold{{\underline{\red{Q}\pink{uest}\green{ion}\purple{:-}}}}}

  • To find the the distance of object from image (v + u) ?

{\bold{{\underline{\red{S}\pink{olut}\green{ion}\purple{:-}}}}}

  • Magnification (m) = \bold{\frac{Image\:height\:(h')}{Object\:height\:(h)}}

  • Magnification (m)  =  \bold{\frac{40}{10}}

  • Magnification (m) = 4 cm

  • \frac{-v}{u} = 4
  • - v = 4u

        Also:

  • Magnification (m) = \bold{\frac{-\: Image\:distance\:(-v)}{Object\:distance\:(u)}}

  • \bold{\frac{1}{Image\:distance\:(\frac{1}{v} )}\: +\: \frac{1}{Object\:distance\:(\frac{1}{u} )} \:=\:\frac{1}{Focal\:length\:(\frac{1}{f} )} }

  • \bold{ \frac{1}{u} \: -\: {\frac{1}{4u}\:=\:\frac{1}{-30} }}

  • Lcm = - 4u

  • \frac{-4\:+\: 1}{-4u}\:=\:\frac{1}{-30}

  • \frac{-3}{-4u}\:=\:\frac{1}{-30}

  • \frac{1}{-4u}\:=\:\frac{1}{-30\:*\: -3}

  • 4u = - 90

  • u = \frac{-90}{4}

  • u = -22.50
  • v = - 90

The the distance of object from image (v + u) = -(90 + 22.50)

  • v + u = - 112.50

\rule{200}{2}

Similar questions