Question

A concentrated solution of HClis38 M. what quantity of the concentrated acid would be required to make 250. mL of a 1.00 M HCl solution?

Answer it
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Answer 1

=>The molarity of the concentrated acid solution that we will use to make 250 ml of 1.00 M HCl solution is 38 molar.

So, volume of 38 M HCl required to make 250 ml 1.00 M HCl =?

First, we will find out how many moles of HCl does 250 ml of 1 M HCl have.

Volume of solution = 250 mL => 0.25 L

Molarity = 1 M

Let moles of HCl required be x.

Molarity = moles of HCl/litres of solution

1 = x/0.25

x= 0.25 moles of HCl

Now, we will find what volume of 38 M HCl solution has 0.25 moles of HCl:

Molarity = 38 M

Volume of solution= x

Moles of HCl = 0.25 moles of HCl

Molarity = (moles of HCl)/litres of solution

38 = 0.25/x

x= 0.25/38

x=1/4 * 38

x= 1/152

x= 0.00658 L

x= 0.00658 X 1000 mL => x= 6.58 mL

Hence, 6.58 millilitres of the 38 M concentrated HCl solution is needed.