Question

A concrete slab of mass 400 kg accelerates down a concrete slope inclined at 35". The µ kinetic between the slab and slope is 0.60. Determine the acceleration of the block ​

Answer 1

Answer:

.082 g

Explanation:

normal force = 400 g cos 35

friction force up slope = .6 (400 g) cos 35

weight component down slope = 400 g sin 35

400 a = 400 g sin 35 - .6 (400 g cos 35)

a = g (sin 35 - .6 cos 35) = .082 g

Answer 2

The acceleration will be 0.82.

Given: ass 400 kg accelerates down a concrete slope inclined at 35"

To find: acceleration

Solution:

Displacement is outlined as the change available of an object. It is a heading size and has a management and size. It is presented as an missile that points from the offset position to the ending position. For example- If an object moves from A position to B, before the object’s position changes. This change available of an object is famous as Displacement.

Distance and dislocation are two quantities that appear to mean the alike but are clearly various accompanying various significations and definitions. Distance is the measure of “by what method much ground an object has enclosed all the while allure motion” while dislocation refers to the measure of “by virtue of what unusual of place is an object.” In this item, allow us believe the distinctness 'tween distance and dislocation

Let simplify it,

normal force = 400 g cos 35

friction force up slope = .6 (400 g) cos 35

weight component down slope = 400 g sin 35

400 a = 400 g sin 35 - .6 (400 g cos 35)

a = g (sin 35 - .6 cos 35)

= .082 g

So Value of a is 0.82g.

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