Question

a concrete slab weight is 180 Newton when it is fully submerged under thus its Apparent weight is 108 Newton calculate the density of the sea water if the volume of the sea water displaced by the concrete slab is 4800 cm^3 g = 9.81
(please do the last step detailed my calculated answer is coming wrong)
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Answer 1

Answer:

a concrete slab weight is 180 Newton when it is fully submerged under thus its Apparent weight is 108 Newton calculate the density of the sea water if the volume of the sea water displaced by the concrete slab is 4800 cm^3 g = 9.81

(please do the last step detailed my calculated answer is coming wrong)

Answer 2

Answer: 1530 kg/m³

Explanation:

Given:

weight of the body = 180 N

Apparent Weight of the body = 108 N

Volume of liquid displaced = 4800cm³

As the volume is in cm³ ...Let's first convert it into m³

which is 4800×(10^-²)³ = 4800×10^-6

g = 9.8

As we know ,

Buoyant Force = Actual weight - Apparent Weight

= 180N - 108N

= 72N

Now,

We know that ,

Buoyant Force = sigma × V × g

72N = sigma × 4800 × 9.8

Now by the shifting sigma to the LHS we get 1530kg/m³approx. (no. May vary )