Question

A condenser having a capacity of 6uF is charged to 100V and is then joined to an uncharged condenser of 14uF and then removed The ratio of the charges on 6uF and 14uF and the potential of 6uF will be: ​

Answer 1

Answer:

16\40 and 30 volts

Explanation:

Let q1,q2 be the charges on two condensers

∴V=

q1

6

=

q2

14

⇒

q1

q2

=

6

14

=

3

7

Also q1+q2=600⇒q1+

14

6

q1=600

⇒q1=

600

20

×6

∴V=

q1

6

=

600

20

=30 volt