Question

). A condenser is charged to an energy of 0.5J.
After disconnecting from the battery the
space between the two plates of the
condenser is filled with a dielectric slab of
er=5. Its new energy is
(A) 0.1J
(B) 0.5J
(C) 2.5J
(D) Zero​

Answer 1

Answer:

c one bro ez it's very very easy

Answer 2

Answer:

(A) 0.1J

Explanation:

U=0.5J

K=$E$/$E_0$ = $E_r$ = 5

U= U/k

= 0.5/5

= 0.1J            (option A)

hope this helps :)