Question

A condenser of capacity 500 pF is charged to
a potential 100V. Find the charge on the
condenser and energy stored in it. (500 pF
1​

Answer 1

Answer:

As C=Q/V, SO Q=VC

Q= 100*500= 500*10^2 *10^-12

= 500*10^-10 coulumb

= 5*10^-8 C

Energy =U= QV

= 5*10^-8*100

= 5*10^-6 JOULES

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Answer 2

Answer:

The charge and energy stored in the condenser are 5×10⁻⁸C and

2.5 ×10⁻⁶J respectively.

Explanation:

The charge on the condenser is given as,

$Q=CV$           (1)

Q=charge on the condenser

C=capacity of the condenser

V=potential across the condenser

From the question we have,

C=500pF=500×10⁻¹²=5 ×10⁻¹⁰

V=100v

By putting the value of C and V in equation (1) we get;

$Q=5\times 10^-^1^0\times 100=5\times 10^-^8C$     (2)

The energy stored(E)  in the condenser is given as,

$E=\frac{1}{2}CV^2$      (3)

By putting the values in equation (3) we get;

$E=\frac{1}{2}\times 5\times 10^-^1^0\times (100)^2$

$E=2.5\times 10^-^1^0\times 10^4$

$E=2.5\times 10^-^6J$

Hence, the charge and energy stored in the condenser is 5×10⁻⁸C and

2.5 ×10⁻⁶J respectively.