Question

a conductiity has 0.02 solution and electrolye was found to be at 298k

Answer 1

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ANSWER

Given for 0.02 N solution

R= 210 ohm,

a

1

=0.88cm

−1

∴K=

210

1

×0.88

4.19×10

−3

Scm

−1

Also λ=1000n=

0.02

4.19×10

−3

×1000

209.5Scm

2

eq

−1

Also ∧

M

=

M

k×1000

=

0.02

4.19×10

−3

×1000

419Scm

2

mole

−1