A conducting circular loop is placed in a uniform magnetic field 0.04 T with its plane perpendicular to the magnetic field. The radius of the loop starts shrinking at 2 mms-1 The induced emf in the loop when the radius is 2 cm is
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0
Answer:
Hope it help you
Explanation:
Induced emf in the loop is given by
e=−B.
dt
dA
where A is the area of the loop.
e=−B.
dt
d
(πr
2
)=−Bπ2r
dt
dr
r=2 cm=2×10
−2
m
dr=2 mm=2×10
−3
m
dt=1s
e=−0.04×3.14×2×2×10
−2
×
1
2×10
−3
V
=0.32π×10
−5
V
=3.2π×10
−6
V
=3.2πμV.
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ϕ=B/2πr
⇒dϕ/dt =2πr. dr/dt
⇒ when r=2×10^−2 m and dr/dt
=10 ^−3 ms ^−1
⇒e= dϕ/dt
=2× 22/7 ×(2×10-² )(0.02)×10³
=2.5μv.
Hence, the answer is 2.5μv.
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