Question

A conducting ring of radius 1 m is placed in an uniform magnetic field B of 0.01 T oscillating with frequency 100 Hz with its plane at right angle to B. What will be the induced electric field?

Answer 1

V=∫E.dl=-dФb/dt
E(2πr)=d(πr²B)/Dr =πr²dB/dt
E=r/2dB/dt= rBω/2
E=(r/2)(B)(2πn)
E=(1/2)×0.01×2π×100=π volts/m.

Answer 2

A conducting ring of radius 1 m is placed in an uniform magnetic field B of 0.01 T oscillating with frequency 100 Hz with its plane at right angle to B. What will be the induced electric field?

Solution to the answer:

We know that

V=∫E.dl=

V=-dФb/dt

Now

E(2πr)=d(πr²B)/Dr =πr²dB/dt

And

E=rBω/2

E=(r/2)(B)(2πn)

E=(1/2)×0.01×2π×100=π volts/m.

Hence the answer is π volts/m