Physics, asked by danish1582, 11 months ago

A conducting ring of radius r is placed perpendicularly inside a time varying magnetic field given by b=b0 +at

Answers

Answered by aqsaahmed19945
3

ϕ = π R^2 B

e = π R^2 dB dt

= π R^2 β

current = e / r

If dl would be a small element of ring.

de = ( e / 2πR ) dl

de = ( r / 2πR ) dl

V = de−idr

= e / 2πR dl − er r / 2πR dR = 0

All points would have same potential :

∮E. dl¯= d ϕ dt

El = π R^2 dB / dt

E 2πR = π R^ 2β

E = βR / 2

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