Question

A conducting rod moves with constant
velocity v. perpendicular to the long,
straight wire carrying a current I as
shown compute that the emf
generated between the ends of the
rod:
​

Answer 1

Answer:

∴ ε(t) = vµ0Iℓ

2π(r0 + vt)

Explanation:

since speed is uniform and magnetic force on electron inside rod is pointing downwards so force will be  Fm = evB(r)

emf wil be equal to work done we can calculate it as using this formula:

ε(t) = Fmℓ /e