A conducting rod of length I, mass m and resistance R is falling freely through a uniform magnetic field B which is perpendicular to the plane of paper as shown in figure Find terminal velocity (vt) of this rod. [Ans :mgR/B²l²]
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The emf driving the current is equivalent to vBd where d is the length of the segment of wire interfacing the rails.
(The work done per unit charge (voltage) is vBd, when a charge moves from one end of the moving wire to the opposite end.)
The present streaming in the circuit will be I = vBd/R,
where R is the obstruction of the circuit.
Subsequently v = IR/Bd = 0.5 A*6 Ω/(2.5 T*1.2 m) = 1 m/s.
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