Question

a conducting rod of length l with one end pivoted is rotated with a uniform angular speed omega in vertical plane normal to a uniform magnetic field B. deduce an expression

Answer 1

As given E = rate of change of magnetic flux

E = B.A/T

(Here T will be the time taken by the rod, because in this time,emf rises from peak to zero)

Also ω = 2$\pi[/tex/T</h3><h3>So T = 2[tex]\pi$/ω

E = B.$\pi$ L (square)/2$\pi$ω

So, E = BWL(square)/2

Answer 2

Answer: zero

Explanation: