Question

A conducting rod of length placed on a horizontal table in
north-south direction. It carries a current of 5 A from south to
north. Find the direction and magnitude of the magnetic force
acting on the rod. Given that the Earth's magnetic field at the
place is 0-6 x 10-4T and angle of dip is π/6​

Answer 1

Answer:

force will act towards West

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Answer 2

The magnitude of the magnetic force is $7.48\times10^{-4}\ N$.

The direction of magnetic force towards west.

Explanation:

Given that,

Current = 5 A

Magnetic field of earth $B_{e}=0.6\times10^{-4}\ T$

Dip angle $\theta=\dfrac{\pi}{6}$

Suppose, The length of the rod is 2.5 m.

We need to calculate the horizontal component of the earth magnetic field

Using formula of horizontal component

$B_{H}=B_{e}\cos\theta$

Put the value into the formula

$B_{H}=0.6\times10^{-4}\cos\dfrac{\pi}{6}$

$B_{H}=0.0000599\ T$

$B_{H}=5.99\times10^{-5}\ T$

We need to calculate the magnitude of the magnetic force

Using formula of magnetic force

$F_{B}=Bil$

Put the value into the formula

$F_{B}=5.99\times10^{-5}\times5\times2.5$

$F_{B}=0.000748\ N$

$F_{B}=7.48\times10^{-4}\ N$

According to the right hand rule,

The direction of magnetic force is perpendicular to the direction of current .

So, The direction of magnetic force towards west because the direction of current north to east.

Hence, The magnitude of the magnetic force is $7.48\times10^{-4}\ N$.

The direction of magnetic force towards west.  

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Topic : magnetic force  

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