Question

A conducting sphere 45 cm in diameter carries an excess of charge, and no other charges are present. You measure the potential of the surface of this sphere and find it to be 14 kv relative to infinity. The excess charge on this sphere is

Answer 1

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Answer 2

Answer:

0.35μC is the charge(excess) on the given sphere of 45cm.

Explanation:

Potential(V) on the surface of a sphere is given the Statement,

$V=\frac{Q}{4\pi E_{0}R }$

where Q = Sphere's charge

E₀=Permittivity of the free space

R= Radius of the sphere

The potential on the given sphere arises because of the presence of excess charge.

So the excess charge on the given sphere can be calculate using,

$V=\frac{Q}{4\pi E_{0}R }\\Q=V*4\pi *E_{0} *R\\Given,diameter=45cm \\radius=\frac{45}{2} *10^{-2} =22.5*10^{-2} m\\Q=14000*4*3.14*8.85*10^{-12} *22.5*10^{-2}\\Q=0.35*10^{-6} C$

Q=0.35μC

0.35μC is the excess charge on the given sphere of 45cm.