A conducting sphere of radius 5 cm has a charge of 31-41 MC. Calculate the
surface density of charge.
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1
Answer:
Electric field intensity (E) at a distance (d) from the centre of a sphere containing net charge q is given by the relation,
E=
4π∈
0
d
2
q
Where,
q= Net charge = 1.5×5
3
N/C
d= =20cm=0.2m
And,
4π∈
0
1
=9×5
9
Nm
2
C
−2
∴q=E(4π∈
0
)d
2
=
9×10
9
1.5×5
3
×(0.2)
2
=6.67×10
9
C
=6.67nC.
Because the electric field lines point radially inwards, the charge on the sphere is negative. Therefore, the net charge on the sphere is 6.67 nC.
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