Question

A conducting sphere of radius 5 cm has a charge of 31.41 mew calculate the surface density of charge

Answer 1

Answer:

The surface density of charge of the sphere is 999.8 C/m ^ 2

Explanation:

The radius of the sphere (r) = 5 cm

= 5 × 10 ^ -2 m

Thus, Area (a) = 314.16 × 10 ^ -4 m^2

Charge of sphere (q) = 31.14 micro coulomb

= 31.14 × 10 ^ -6 C

The surface density of charge = q/a

= 31.41×10^-6 C/314.16 × 10 ^ -4 m^2

= 999.8 C/m ^ 2