a conducting sphere of radius R and carrying a charge q is joined to a conducting sphere of radius 2R, and carrying a charge -2q.the charge flowing between them will be
Answers
Answered by
2
Answer:
At equilibrium, the potential of the two spheres are same.
Potential is directly proportional to charge/radius.
total charge of the combination=Q
Let us assume that a charge x flows between them
charge on larger sphere will be x and charge on smaller sphere will be Q - x
Potential on smaller sphere = k (Q - x) / R
Potential on larger sphere = k x /2R
Equating the potentials
k (Q - x) / R = k x /2R
Q - x = x/2
3x/2 = Q
x = 2Q/3
Thus a charge of 2Q/3 will flow between them
HOPE THIS HELPS YOU................
PLZ MARK AS BRAINLEST.........
Similar questions