a conducting spherical shell is given charge +2Q . a point charge +Q is kept inside the shell at point o as shown now if charge +Q is, shifted from point o to point p then magnitude of electric field at point A outside the shell will be
Answers
Answered by
6
Explanation:
Electric potential due to point charge =k
R
q
Electric potential due to inner surface of shell =−
2R
kq
and electric potential due to outer surface of shell =
3R
kq
V=k
R
q
−
2R
kq
+
3R
kq
=
R
kq
[1−
2
1
+
3
1
]
=
6R
k5q
Answered by
0
Answer:
Electric field at point A is k Q [1/(r1+r2)^2 +2/r2^2]
Explanation:
let, the distance of point p from the shell be r1
and distance of point A from the shell be r2
so, the distance 0f point A from point p will be r1 + r2
now, electric field at point A due to charge +Q
E1 = k Q/(r1+r2)^2
electric field at point A due to the shell
E2 = k 2Q/r2^2
since, the direction of both E1 and E2 are same
net electric field at point A
E = E1+E2
E = k Q [1/(r1+r2)^2 +2/r2^2]
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