Question

A conducting square loop of side i and resistance r moves in its plane with a uniform velocity v perpendicular to one of its sides. A uniform and constant magnetic field b exists along the perpendicular to the plane of the loop in fig. The current induced in the loop is

Answer 1

Answer:

No current is induced.

Explanation:

The figure is attached.

According to the problem the conducting square has the side of i and resistance or r

its velocity v

And the magnetic field exist is b

Therefore the induced emf across AB and CD[from the fig]:

e =bvl

Now by applying  KVL in the equivalent circuit,

we get

E−E+ir=0

or, i=0

As the potential difference is zero therefore no current is induced in the circuit.