a conducting surface of 5cm is chargee to 15microcm
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Let common potential = V
q1 = 4πεor1 V , q2 = 4πεor2 V
σ1 = q1/4πr12 ; σ2 = q2/4πr22
σ1/σ2 = (q1/q2) (r22/r12) = r2/r1 = 10/5 = 2 : 1
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