Question

a conducting surface of radius 5 CM has a charge of 31.41 .
calculate surface density
of charge​

Answer 1

Answer:

Given info : a conducting sphere of radius, r = 5cm has a charge of 31.41 μC

Explanation:

To find : the surface charge density of the conducting sphere.

Solution : surface area of conducting sphere, A = 4πr²

= 4 × 3.141 × (0.05 m)²

= 0.03141 m²

Now surface charge density = charge/surface area

= (31.41μC)/(0.03141 m²)

= (31.41 × 10¯⁶)/(0.03141) C/m²

= 10¯³ C/m²

therefore the surface charge density of conducting sphere is 10¯³ C/m²