Question

A conducting thick copper rod of length
1m carries a current of I5A and is located
the earths equator. There the magnetic flux
lines of Earth's magnetic field are horizontal
with field of 1.3 x 10^4T, south to north.
The magnitude and direction of force on rod
when it is oriented so that current flows
from west to east are?

Please step by step

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Answer 1

Answer:

Write a program that stores the name of each month in an array of Strings, and the rainfall for each month of the year into an array of doubles. The program should determine the total rainfall for the year, the average monthly rainfall, and the months with the most and least amount of rain. You will need: Two one-dimensional arrays - one to store the names of each month and another to store the rainfall for each month. (What would be the size of these arrays?)

Use an initialization list to store the names of each month into the String array. A for loop to receive the values of rainfall. You should refer to your string array to get the names for the appropriate month. The rainfall values should be stored in the doubles array. Make sure the user does not enter a negative value for rainfall. (Use a while loop for this part)

A for loop to compute the running sum A variable to store the average A for loop (with a nested if statement) to determine the largest amount of rainfall in the doubles array You need to refer to the String array to indicate the month with the largest rainfall.

A for loop (with a nested if statement) to determine the smallest amount of rainfall You need to refer to the String array to indicate the month with the largest rainfall.

Answer 2

Given:

Length of conducting rod  (L) = 1 m

Current through the rod (I) = 15 A

Earth's magnetic field (B) = 1.3 × 10⁴ T

To find:

The magnitude and direction of resulting force experienced by the rod.

Explanation:

• A conducting rod of length (L) that has a current I flowing through it in a magnetic field B experiences a Force (F) such that the rod directs itself in such a way that it will experience minimum torque.

• The magnitude of this force is given by

                              $F = I L B sin\alpha$

         where, $\alpha$ is the angle between the rod and the magnetic field.

Solution:

Step 1

We know,

Here the rod directs from west to east and magnetic field lies perpendicular, from south to north .

Hence, α = 90°

Therefore,

Substituting the values, we get

$F = (15)(1)(1.3)10^{4} sin(90)$ ; or

F = 19.5 × 10⁴N

Step 2

The direction of force experienced by the rod is given by Right hand rule , where central finger is the current , index finger is the magnetic field then, the thumb gives us the direction of the force.

applying this law,

We conclude that the force will act downwards .

Final answer:

The force experienced by the rod has a magnitude 19.5 × 10⁴ and will act in the downward direction.