Question

A conducting wire carries a current of 9.65 A. Rate of flow electrons per second is:
(a) 3 x 10 power 20
(b) 6 x 10 power 20
(c) 3 x 10 power 19
(d) 6 x 10 power 19

Answer 1

Explanation:

The current is defined as rate of flow of charged particle.i.e.

i =tQ

Hence the charge flown is,

Q =i t

Hence Q =1.0×1=1C

The charge Q is due to electrons, therefore,

Q =N×e

Here Q =1C

If N is number of electrons passing and e is the electronic charge of value 1.6×10−19

Then,

N =eQ=1.6×10−191=0.625×1019electrons

Answer 2

Answer:

6,× 10 bpower 20 ( i think its correct )