A conduction gring of radius 1 meter is placed in an uniform magnetic field b
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A conducting ring of radius 1 m is placed in an uniform magnetic field B of 0.01 T oscillating with frequency 100 Hz with its plane at right angle to B. What will be the induced electric field?
Solution to the answer:
We know that
V=∫E.dl=
V=-dФb/dt
Now
E(2πr)=d(πr²B)/Dr =πr²dB/dt
And
E=rBω/2
E=(r/2)(B)(2πn)
E=(1/2)×0.01×2π×100=π volts/m.
Hence the answer is π volts/m
Solution to the answer:
We know that
V=∫E.dl=
V=-dФb/dt
Now
E(2πr)=d(πr²B)/Dr =πr²dB/dt
And
E=rBω/2
E=(r/2)(B)(2πn)
E=(1/2)×0.01×2π×100=π volts/m.
Hence the answer is π volts/m
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