Question

a conductivity cell has two platinum electrodes separate by a distance 1.5 cm and the cross sectional area of ecah electrode is 4.5ohm sq cm. ​

Answer 1

Answer:

Molar conductivity= Concentration of electrolyte(C)Specific conductance (K)

⇒K=∧m×C=194.5Ω−1cm2mol−1×0.05molL−1

⇒K=9.725Ω−1cm2L−1                1L=1000cm3;1L−1=10−3cm−3

as R1=KlA           A⟶ Area of cross-section of cell; l⟶ length of electrode cell; R⟶ Resistance

⇒R1=9.725Ω−1cm2×10−3cm−30.50cm1.50cm2=0.029Ω−1

⇒R=34.27Ω

as V=IR                 V⟶ Electric potential; I⟶ Current 

⇒I=RV=34.27Ω5.0V=0.145Ampere

Thus, 

Explanation:

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Answer 2

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