a conductivity cell is filled with 0.1m kcl. The resistance of the kcl solution is 200ohm. The same conductivity cell is filled with 0.03M NaCl and the cell resistance is 500 ohm. What is the conductivity and molar conductivity of 0.03M NaCl? The conductivity of 0.1m kcl solution is 1.29S /m.
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Answer:
For KCl solution:
κ=
R
b
Here κ is the conductivity, b is the cell constant and R is the resistance.
0.00189S/cm=
410.5ohm
b
Hence, the cell constant b is 0.776/cm
For CaCl
2
solution:
κ=
R
b
=
990ohm
0.776/cm
=0.000784S/cm
The molar concentration is C=
0.5L×111g/mol
11g
=0.198M
The molar conductivity of CaCl
2
solution is
C
1000 κ
=
0.198
1000×0.000784
=3.956Scm
2
/mol
Hence, the correct option is A
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