Question

A conductivity cell was filled with 0.02M solution which has a specific conductance of . If its resistance is 82.4 ohm at , the cell constant is​

Answer 1

Answer:

Here is your Answer

Explanation:

The specific conductance (κ) is the product of cell constant (  

a

l

​  

) and reciprocal of resistance (  

R

1

​  

).  

Hence,  

a

l

​  

=κ×R=2.768×10  

−3

ohm  

−1

cm  

−1

×82.4ohm=0.2281cm  

−1

.