Question

a conductor carries a current of 0.2 ampere find the amount of charge that will pass through the cross section of the conductor in 30 seconds how many electrons will flow in the time interval if the charge of an electron is 1.6 multiplied by 10 raise to the power of minus 19 coulomb ​

Answer 1

Explanation:

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Answer 2

Answer:

I=0.2A

t=30s

Q=It

Q=0.2×30=6c

And no of electron is

N=q/e

=6/1.6×10^-19=3.75×10^10

Explanation: