Question

a conductor carries a current of 0.2 ampere . find the amount of charge that will pass through the cross section of the conductor in 30s . how many electrons will flow in this time interval if the charge on one electron is 1.6*10 raise to -19

Answer 1

Answer:

Q=ne

i=q/t

Explanation:

therefore,         it=ne=q

where,     i=current   n=number of electrons

n=it/e

   = 0.2*30/1.6*10^-19.