A conductor carries a current of 0.2A Find the amount of charge that pass through the cross section of the conductor in 30s. How many electrons will flow in this time interval if the charge on one electron is 1.6X10 to the power of -19 .
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I = 0.2 A, t = 30 s
(a) Charge = Current x time
Or, Q = I x t = 0.2 x 30 = 6 C
(b) If n electrons flow and e is the charge on one electron, then total charge passed Q = ne
Therefore, n = Q/e = 6 / (1.6 x 10-19) = 3.75 x 1019.
(a) Charge = Current x time
Or, Q = I x t = 0.2 x 30 = 6 C
(b) If n electrons flow and e is the charge on one electron, then total charge passed Q = ne
Therefore, n = Q/e = 6 / (1.6 x 10-19) = 3.75 x 1019.
Answered by
7
Answer:
I = 0.2 A, t = 30 s
(a) Charge = Current x time
Or, Q = I x t = 0.2 x 30 = 6 C
(b) If n electrons flow and e is the charge on one electron, then total charge passed Q = ne
Therefore, n = Q/e = 6 / (1.6 x 10-19) = 3.75 x 1019.
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