Question

A conductor carries a current of 30ma the number of electrons passing through it in 1 minute are about

Answer 1

$\huge \bf{hey}$


$\huge{ \mathfrak{here \: is \: answer}}$

given - current (i)=30 mili ampere

means 30*10^-3

3*10^-4 ampere

time= 1 min= 60 sec

no of electrons=?

according to question

q= ne

e= 1.6*10^-19

q= ne

I= q/t.

q=it

q= 3*10^-4*60

q= 180*10^-4

q= 1.8*10^-2

q= ne

n= q/e

$n = \frac{1.8 \times {10}^{ - 2} }{1.6 \times {10}^{ - 19} }$
$n = \frac{1.8 \times {10}^{ - 2 } \times {10}^{19} }{1.6}$


$n = \frac{1.8 \times {10}^{17} }{1.6}$

$\bf{n= 1.125 \times {10}^{17} electrons}$


$\huge \boxed{ \boxed { \boxed{hope \: it \: helps}}}$

$\huge{ \mathbb{THANKS}}$