A conductor carry current of 0.4 ampere find the am amount of charge that will pass through the cross section of the conductor in 1.5 minutes how many electrons flow in time intervals
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charge = 0.4 ×1.5 =0.6
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q=it=>q=.4*1.5*60=36
and q=ne
36=n*1.6*10^-19
n=(36/1.6)*10^19=(9/4)10^20=2.2*10^20 electron travel
and q=ne
36=n*1.6*10^-19
n=(36/1.6)*10^19=(9/4)10^20=2.2*10^20 electron travel
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